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23.5 Examples
The example program below uses the Monte Carlo routines to estimate the value of the following 3-dimensional integral from the theory of random walks, The analytic value of this integral can be shown to be I = \Gamma(1/4)^4/(4 \pi^3) = 1.393203929685676859.... The integral gives the mean time spent at the origin by a random walk on a body-centered cubic lattice in three dimensions.
For simplicity we will compute the integral over the region (0,0,0) to (\pi,\pi,\pi) and multiply by 8 to obtain the full result. The integral is slowly varying in the middle of the region but has integrable singularities at the corners (0,0,0), (0,\pi,\pi), (\pi,0,\pi) and (\pi,\pi,0). The Monte Carlo routines only select points which are strictly within the integration region and so no special measures are needed to avoid these singularities.
#include <stdlib.h> #include <gsl/gsl_math.h> #include <gsl/gsl_monte.h> #include <gsl/gsl_monte_plain.h> #include <gsl/gsl_monte_miser.h> #include <gsl/gsl_monte_vegas.h> /* Computation of the integral, I = int (dx dy dz)/(2pi)^3 1/(1-cos(x)cos(y)cos(z)) over (-pi,-pi,-pi) to (+pi, +pi, +pi). The exact answer is Gamma(1/4)^4/(4 pi^3). This example is taken from C.Itzykson, J.M.Drouffe, "Statistical Field Theory - Volume 1", Section 1.1, p21, which cites the original paper M.L.Glasser, I.J.Zucker, Proc.Natl.Acad.Sci.USA 74 1800 (1977) */ /* For simplicity we compute the integral over the region (0,0,0) -> (pi,pi,pi) and multiply by 8 */ double exact = 1.3932039296856768591842462603255; double g (double *k, size_t dim, void *params) { double A = 1.0 / (M_PI * M_PI * M_PI); return A / (1.0 - cos (k[0]) * cos (k[1]) * cos (k[2])); } void display_results (char *title, double result, double error) { printf ("%s ==================\n", title); printf ("result = % .6f\n", result); printf ("sigma = % .6f\n", error); printf ("exact = % .6f\n", exact); printf ("error = % .6f = %.1g sigma\n", result - exact, fabs (result - exact) / error); } int main (void) { double res, err; double xl[3] = { 0, 0, 0 }; double xu[3] = { M_PI, M_PI, M_PI }; const gsl_rng_type *T; gsl_rng *r; gsl_monte_function G = { &g, 3, 0 }; size_t calls = 500000; gsl_rng_env_setup (); T = gsl_rng_default; r = gsl_rng_alloc (T); { gsl_monte_plain_state *s = gsl_monte_plain_alloc (3); gsl_monte_plain_integrate (&G, xl, xu, 3, calls, r, s, &res, &err); gsl_monte_plain_free (s); display_results ("plain", res, err); } { gsl_monte_miser_state *s = gsl_monte_miser_alloc (3); gsl_monte_miser_integrate (&G, xl, xu, 3, calls, r, s, &res, &err); gsl_monte_miser_free (s); display_results ("miser", res, err); } { gsl_monte_vegas_state *s = gsl_monte_vegas_alloc (3); gsl_monte_vegas_integrate (&G, xl, xu, 3, 10000, r, s, &res, &err); display_results ("vegas warm-up", res, err); printf ("converging...\n"); do { gsl_monte_vegas_integrate (&G, xl, xu, 3, calls/5, r, s, &res, &err); printf ("result = % .6f sigma = % .6f " "chisq/dof = %.1f\n", res, err, s->chisq); } while (fabs (s->chisq - 1.0) > 0.5); display_results ("vegas final", res, err); gsl_monte_vegas_free (s); } gsl_rng_free (r); return 0; } |
With 500,000 function calls the plain Monte Carlo algorithm achieves a
fractional error of 0.6%. The estimated error sigma
is
consistent with the actual error, and the computed result differs from
the true result by about one standard deviation,
plain ================== result = 1.385867 sigma = 0.007938 exact = 1.393204 error = -0.007337 = 0.9 sigma |
The MISER algorithm reduces the error by a factor of two, and also correctly estimates the error,
miser ================== result = 1.390656 sigma = 0.003743 exact = 1.393204 error = -0.002548 = 0.7 sigma |
In the case of the VEGAS algorithm the program uses an initial warm-up run of 10,000 function calls to prepare, or “warm up”, the grid. This is followed by a main run with five iterations of 100,000 function calls. The chi-squared per degree of freedom for the five iterations are checked for consistency with 1, and the run is repeated if the results have not converged. In this case the estimates are consistent on the first pass.
vegas warm-up ================== result = 1.386925 sigma = 0.002651 exact = 1.393204 error = -0.006278 = 2 sigma converging... result = 1.392957 sigma = 0.000452 chisq/dof = 1.1 vegas final ================== result = 1.392957 sigma = 0.000452 exact = 1.393204 error = -0.000247 = 0.5 sigma |
If the value of chisq
had differed significantly from 1 it would
indicate inconsistent results, with a correspondingly underestimated
error. The final estimate from VEGAS (using a similar number of
function calls) is significantly more accurate than the other two
algorithms.
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